j^2+10j-28=11

Solution for j^2+10j-28=11 equation:

Simplifying
j2 + 10j + -28 = 11

Reorder the terms:
-28 + 10j + j2 = 11

Solving
-28 + 10j + j2 = 11

Solving for variable 'j'.

Reorder the terms:
-28 + -11 + 10j + j2 = 11 + -11

Combine like terms: -28 + -11 = -39
-39 + 10j + j2 = 11 + -11

Combine like terms: 11 + -11 = 0
-39 + 10j + j2 = 0

Factor a trinomial.
(-13 + -1j)(3 + -1j) = 0

Subproblem 1
Set the factor '(-13 + -1j)' equal to zero and attempt to solve:

Simplifying
-13 + -1j = 0

Solving
-13 + -1j = 0

Move all terms containing j to the left, all other terms to the right.

Add '13' to each side of the equation.
-13 + 13 + -1j = 0 + 13

Combine like terms: -13 + 13 = 0
0 + -1j = 0 + 13
-1j = 0 + 13

Combine like terms: 0 + 13 = 13
-1j = 13

Divide each side by '-1'.
j = -13

Simplifying
j = -13
Subproblem 2
Set the factor '(3 + -1j)' equal to zero and attempt to solve:

Simplifying
3 + -1j = 0

Solving
3 + -1j = 0

Move all terms containing j to the left, all other terms to the right.

Add '-3' to each side of the equation.
3 + -3 + -1j = 0 + -3

Combine like terms: 3 + -3 = 0
0 + -1j = 0 + -3
-1j = 0 + -3

Combine like terms: 0 + -3 = -3
-1j = -3

Divide each side by '-1'.
j = 3

Simplifying
j = 3
Solution
j = {-13, 3}